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Data Structures and Algorithms
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  • Problems
    • LeetCode
      • 1. Two Sum
      • 3. Longest Substring Without Repeating Characters
      • 5. Longest Palindromic Substring
      • 11. Container With Most Water
      • 15. 3 Sum
      • 19. Remove Nth Node From End of List
      • 20. Valid Parentheses
      • 33. Search in Rotated Sorted Array
      • 49. Group Anagrams
      • 53. Maximum Subarray
      • 55. Jump Game
      • 56. Merge Intervals
      • 76. Minimum Window Substring
      • 98. Validate Binary Search Tree
      • 105. Construct Binary Tree from Preorder and Inorder Traversal
      • 121. Best Time to Buy and Sell Stock
      • 133. Clone Graph
      • 141. Linked List Cycle
      • 152. Maximum Product Subarray
      • 153. Find Minimum in Rotated Sorted Array
      • 200. Number of Islands
      • 206. Reverse Linked List
      • 207. Course Schedule
      • 217. Contains Duplicate
      • 226. Invert Binary Tree
      • 238. Product of Array Except Self
      • 242. Valid Anagram
      • 297. Serialize and Deserialize Binary Tree
      • 347. Top K Frequent Elements
      • 417. Pacific Atlantic Water Flow
      • 424. Longest Repeating Character Replacement
      • 435. Non-overlapping Intervals
      • 647. Palindromic Substrings
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226. Invert Binary Tree

Description

See https://leetcode.com/problems/invert-binary-tree/

Solution

I used a recursive solution to swap the nodes. This can also be solved by using BFS or DFS.

# Definition for a binary tree node.
# class TreeNode:
#     def __init__(self, val=0, left=None, right=None):
#         self.val = val
#         self.left = left
#         self.right = right
class Solution:
    def invertTree(self, root: Optional[TreeNode]) -> Optional[TreeNode]:
        if root is None:
            return
        root.left, root.right = root.right, root.left
        self.invertTree(root.left)
        self.invertTree(root.right)
        return root
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Last updated 3 years ago